Integrand size = 31, antiderivative size = 157 \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=-\frac {\left (a^2 A-A b^2+2 a b B\right ) x}{\left (a^2+b^2\right )^2}-\frac {\left (2 a A b-a^2 B+b^2 B\right ) \log (\cos (c+d x))}{\left (a^2+b^2\right )^2 d}-\frac {a \left (2 A b^3-a \left (a^2+3 b^2\right ) B\right ) \log (a+b \tan (c+d x))}{b^2 \left (a^2+b^2\right )^2 d}-\frac {a^2 (A b-a B)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))} \]
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Time = 0.49 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.161, Rules used = {3685, 3707, 3698, 31, 3556} \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=-\frac {a^2 (A b-a B)}{b^2 d \left (a^2+b^2\right ) (a+b \tan (c+d x))}-\frac {\left (a^2 (-B)+2 a A b+b^2 B\right ) \log (\cos (c+d x))}{d \left (a^2+b^2\right )^2}-\frac {x \left (a^2 A+2 a b B-A b^2\right )}{\left (a^2+b^2\right )^2}-\frac {a \left (2 A b^3-a B \left (a^2+3 b^2\right )\right ) \log (a+b \tan (c+d x))}{b^2 d \left (a^2+b^2\right )^2} \]
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Rule 31
Rule 3556
Rule 3685
Rule 3698
Rule 3707
Rubi steps \begin{align*} \text {integral}& = -\frac {a^2 (A b-a B)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))}+\frac {\int \frac {-a (A b-a B)+b (A b-a B) \tan (c+d x)+\left (a^2+b^2\right ) B \tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b \left (a^2+b^2\right )} \\ & = -\frac {\left (a^2 A-A b^2+2 a b B\right ) x}{\left (a^2+b^2\right )^2}-\frac {a^2 (A b-a B)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))}+\frac {\left (2 a A b-a^2 B+b^2 B\right ) \int \tan (c+d x) \, dx}{\left (a^2+b^2\right )^2}-\frac {\left (a \left (2 A b^3-a \left (a^2+3 b^2\right ) B\right )\right ) \int \frac {1+\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b \left (a^2+b^2\right )^2} \\ & = -\frac {\left (a^2 A-A b^2+2 a b B\right ) x}{\left (a^2+b^2\right )^2}-\frac {\left (2 a A b-a^2 B+b^2 B\right ) \log (\cos (c+d x))}{\left (a^2+b^2\right )^2 d}-\frac {a^2 (A b-a B)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))}-\frac {\left (a \left (2 A b^3-a \left (a^2+3 b^2\right ) B\right )\right ) \text {Subst}\left (\int \frac {1}{a+x} \, dx,x,b \tan (c+d x)\right )}{b^2 \left (a^2+b^2\right )^2 d} \\ & = -\frac {\left (a^2 A-A b^2+2 a b B\right ) x}{\left (a^2+b^2\right )^2}-\frac {\left (2 a A b-a^2 B+b^2 B\right ) \log (\cos (c+d x))}{\left (a^2+b^2\right )^2 d}-\frac {a \left (2 A b^3-a \left (a^2+3 b^2\right ) B\right ) \log (a+b \tan (c+d x))}{b^2 \left (a^2+b^2\right )^2 d}-\frac {a^2 (A b-a B)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))} \\ \end{align*}
Result contains complex when optimal does not.
Time = 2.89 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.93 \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {\frac {i (A+i B) \log (i-\tan (c+d x))}{(a+i b)^2}-\frac {i (A-i B) \log (i+\tan (c+d x))}{(a-i b)^2}+\frac {2 a \left (\left (-2 A b+a \left (3+\frac {a^2}{b^2}\right ) B\right ) \log (a+b \tan (c+d x))+\frac {a \left (a^2+b^2\right ) (-A b+a B)}{b^2 (a+b \tan (c+d x))}\right )}{\left (a^2+b^2\right )^2}}{2 d} \]
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Time = 0.12 (sec) , antiderivative size = 155, normalized size of antiderivative = 0.99
method | result | size |
derivativedivides | \(\frac {\frac {\frac {\left (2 A a b -B \,a^{2}+B \,b^{2}\right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+\left (-A \,a^{2}+A \,b^{2}-2 B a b \right ) \arctan \left (\tan \left (d x +c \right )\right )}{\left (a^{2}+b^{2}\right )^{2}}-\frac {a^{2} \left (A b -B a \right )}{b^{2} \left (a^{2}+b^{2}\right ) \left (a +b \tan \left (d x +c \right )\right )}-\frac {a \left (2 A \,b^{3}-B \,a^{3}-3 B a \,b^{2}\right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{\left (a^{2}+b^{2}\right )^{2} b^{2}}}{d}\) | \(155\) |
default | \(\frac {\frac {\frac {\left (2 A a b -B \,a^{2}+B \,b^{2}\right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+\left (-A \,a^{2}+A \,b^{2}-2 B a b \right ) \arctan \left (\tan \left (d x +c \right )\right )}{\left (a^{2}+b^{2}\right )^{2}}-\frac {a^{2} \left (A b -B a \right )}{b^{2} \left (a^{2}+b^{2}\right ) \left (a +b \tan \left (d x +c \right )\right )}-\frac {a \left (2 A \,b^{3}-B \,a^{3}-3 B a \,b^{2}\right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{\left (a^{2}+b^{2}\right )^{2} b^{2}}}{d}\) | \(155\) |
norman | \(\frac {-\frac {a \left (A \,a^{2}-A \,b^{2}+2 B a b \right ) x}{a^{4}+2 a^{2} b^{2}+b^{4}}-\frac {b \left (A \,a^{2}-A \,b^{2}+2 B a b \right ) x \tan \left (d x +c \right )}{a^{4}+2 a^{2} b^{2}+b^{4}}-\frac {\left (A a b -B \,a^{2}\right ) a}{d \,b^{2} \left (a^{2}+b^{2}\right )}}{a +b \tan \left (d x +c \right )}+\frac {\left (2 A a b -B \,a^{2}+B \,b^{2}\right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d \left (a^{4}+2 a^{2} b^{2}+b^{4}\right )}-\frac {a \left (2 A \,b^{3}-B \,a^{3}-3 B a \,b^{2}\right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d \,b^{2}}\) | \(234\) |
parallelrisch | \(\frac {-2 A \,a^{2} b^{3}+2 B \,a^{5}-2 A x \tan \left (d x +c \right ) a^{2} b^{3} d -4 B x \tan \left (d x +c \right ) a \,b^{4} d +2 B \ln \left (a +b \tan \left (d x +c \right )\right ) a^{5}-2 A \,a^{4} b +2 B \,a^{3} b^{2}+B \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) \tan \left (d x +c \right ) b^{5}+2 A \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a^{2} b^{3}-4 A \ln \left (a +b \tan \left (d x +c \right )\right ) a^{2} b^{3}-B \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a^{3} b^{2}+B \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a \,b^{4}+6 B \ln \left (a +b \tan \left (d x +c \right )\right ) a^{3} b^{2}-4 A \ln \left (a +b \tan \left (d x +c \right )\right ) \tan \left (d x +c \right ) a \,b^{4}-B \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) \tan \left (d x +c \right ) a^{2} b^{3}+2 B \ln \left (a +b \tan \left (d x +c \right )\right ) \tan \left (d x +c \right ) a^{4} b +6 B \ln \left (a +b \tan \left (d x +c \right )\right ) \tan \left (d x +c \right ) a^{2} b^{3}+2 A x \tan \left (d x +c \right ) b^{5} d -2 A x \,a^{3} b^{2} d +2 A x a \,b^{4} d -4 B x \,a^{2} b^{3} d +2 A \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) \tan \left (d x +c \right ) a \,b^{4}}{2 \left (a +b \tan \left (d x +c \right )\right ) \left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d \,b^{2}}\) | \(407\) |
risch | \(-\frac {2 i a^{4} B x}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) b^{2}}+\frac {x A}{2 i b a -a^{2}+b^{2}}+\frac {2 i B c}{d \,b^{2}}+\frac {4 i a b A c}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d}+\frac {2 i a^{2} A}{\left (i b +a \right ) d \left (-i b +a \right )^{2} \left (-i b \,{\mathrm e}^{2 i \left (d x +c \right )}+a \,{\mathrm e}^{2 i \left (d x +c \right )}+i b +a \right )}-\frac {i x B}{2 i b a -a^{2}+b^{2}}-\frac {2 i a^{4} B c}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d \,b^{2}}-\frac {2 i a^{3} B}{\left (i b +a \right ) d b \left (-i b +a \right )^{2} \left (-i b \,{\mathrm e}^{2 i \left (d x +c \right )}+a \,{\mathrm e}^{2 i \left (d x +c \right )}+i b +a \right )}-\frac {6 i a^{2} B x}{a^{4}+2 a^{2} b^{2}+b^{4}}+\frac {2 i B x}{b^{2}}+\frac {4 i a b A x}{a^{4}+2 a^{2} b^{2}+b^{4}}-\frac {6 i a^{2} B c}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d}-\frac {2 a b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) A}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d}+\frac {a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) B}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d \,b^{2}}+\frac {3 a^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) B}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) d}-\frac {B \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d \,b^{2}}\) | \(530\) |
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Leaf count of result is larger than twice the leaf count of optimal. 311 vs. \(2 (155) = 310\).
Time = 0.31 (sec) , antiderivative size = 311, normalized size of antiderivative = 1.98 \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {2 \, B a^{3} b^{2} - 2 \, A a^{2} b^{3} - 2 \, {\left (A a^{3} b^{2} + 2 \, B a^{2} b^{3} - A a b^{4}\right )} d x + {\left (B a^{5} + 3 \, B a^{3} b^{2} - 2 \, A a^{2} b^{3} + {\left (B a^{4} b + 3 \, B a^{2} b^{3} - 2 \, A a b^{4}\right )} \tan \left (d x + c\right )\right )} \log \left (\frac {b^{2} \tan \left (d x + c\right )^{2} + 2 \, a b \tan \left (d x + c\right ) + a^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) - {\left (B a^{5} + 2 \, B a^{3} b^{2} + B a b^{4} + {\left (B a^{4} b + 2 \, B a^{2} b^{3} + B b^{5}\right )} \tan \left (d x + c\right )\right )} \log \left (\frac {1}{\tan \left (d x + c\right )^{2} + 1}\right ) - 2 \, {\left (B a^{4} b - A a^{3} b^{2} + {\left (A a^{2} b^{3} + 2 \, B a b^{4} - A b^{5}\right )} d x\right )} \tan \left (d x + c\right )}{2 \, {\left ({\left (a^{4} b^{3} + 2 \, a^{2} b^{5} + b^{7}\right )} d \tan \left (d x + c\right ) + {\left (a^{5} b^{2} + 2 \, a^{3} b^{4} + a b^{6}\right )} d\right )}} \]
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Result contains complex when optimal does not.
Time = 1.05 (sec) , antiderivative size = 3485, normalized size of antiderivative = 22.20 \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\text {Too large to display} \]
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Time = 0.32 (sec) , antiderivative size = 197, normalized size of antiderivative = 1.25 \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=-\frac {\frac {2 \, {\left (A a^{2} + 2 \, B a b - A b^{2}\right )} {\left (d x + c\right )}}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac {2 \, {\left (B a^{4} + 3 \, B a^{2} b^{2} - 2 \, A a b^{3}\right )} \log \left (b \tan \left (d x + c\right ) + a\right )}{a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}} + \frac {{\left (B a^{2} - 2 \, A a b - B b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac {2 \, {\left (B a^{3} - A a^{2} b\right )}}{a^{3} b^{2} + a b^{4} + {\left (a^{2} b^{3} + b^{5}\right )} \tan \left (d x + c\right )}}{2 \, d} \]
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Time = 0.58 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.55 \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=-\frac {\frac {2 \, {\left (A a^{2} + 2 \, B a b - A b^{2}\right )} {\left (d x + c\right )}}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} + \frac {{\left (B a^{2} - 2 \, A a b - B b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac {2 \, {\left (B a^{4} + 3 \, B a^{2} b^{2} - 2 \, A a b^{3}\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}} + \frac {2 \, {\left (B a^{4} \tan \left (d x + c\right ) + 3 \, B a^{2} b^{2} \tan \left (d x + c\right ) - 2 \, A a b^{3} \tan \left (d x + c\right ) + A a^{4} + 2 \, B a^{3} b - A a^{2} b^{2}\right )}}{{\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} {\left (b \tan \left (d x + c\right ) + a\right )}}}{2 \, d} \]
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Time = 7.84 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.05 \[ \int \frac {\tan ^2(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (B+A\,1{}\mathrm {i}\right )}{2\,d\,\left (-a^2+a\,b\,2{}\mathrm {i}+b^2\right )}+\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,\left (A+B\,1{}\mathrm {i}\right )}{2\,d\,\left (-a^2\,1{}\mathrm {i}+2\,a\,b+b^2\,1{}\mathrm {i}\right )}-\frac {a^2\,\left (A\,b-B\,a\right )}{b^2\,d\,\left (a^2+b^2\right )\,\left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )}+\frac {a\,\ln \left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )\,\left (B\,a^3+3\,B\,a\,b^2-2\,A\,b^3\right )}{b^2\,d\,{\left (a^2+b^2\right )}^2} \]
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